How to solve this MYSQL Query in php page?

I am new on MYSQL. I have a data in MYSQL database like this (example):-

S.no Book Name Date of Publication Publication ctags
1 ABC 2021 Oxford Free,Video,Audio,Licensed
2 DEF 2020 Cambridge Free,Video,Licensed,
3 GHI 2019 Bloomberry Free,Audio,Licensed
4 JKL 2018 Penguin Free,
5 MNO 2017 Jaya Prakash Licensed
6 PQR 2016 Null Free,Video,Audio

There are multiple tag in the ctags column that are separated with comma. I shared above table only for simple example. In my MYSQL Database there is a column named as ctags and here I am sharing the original mysql querry on php page.

The below code show all the information (s.no 1 to 6) in the page but I want to show those resource that are not ctags with licensed (s.no 4 and 6)

$qnew = "SELECT title, 
                location, 
                access_restrictions 
         FROM title t, location_title lt, location l 
         WHERE t.title_id = lt.title_id 
         AND l.location_id = lt.location_id 
         AND eres_display = 'Y' 
         order by t.title_id DESC limit 0,5";

The below code show nothing but I want to show those resource that are ctags with licensed (s.no 1, 2, 3 and 6).

$qnew = "SELECT title, 
                location, 
                access_restrictions 
         FROM title t, location_title lt, location l 
         WHERE t.title_id = lt.title_id AND l.location_id = lt.location_id 
         AND eres_display = 'Y' 
         AND ctags = 'Licensed' 
         order by t.title_id DESC limit 0,5";

What should I use to get the information from the MYSQL database. Kindly help me to get this.