check the Value for standard manufacturing thickness and display a massage if pass or not

I need to to enter a new value( the standard manufacturing thickness(SMT)) and divid it on /48 then check if the answer < 135 display (pass) if not display (Enter higher value) I tried if else statement but it doesn’t work
and also I want to display the (the standard manufacturing thickness(SMT=)) text input side by side with the MAOP(psi)= text input.

 <body>
  <label for="formulas">Choose a formula:</label>
  <select name="formulas" id="formulas">
  <option value="free">Pipeline Thickness</option>
  </select>
<h2>Enter inputs</h2>
  <label for="P">MAOP(psi)=</label>
  <input type="number" id="P">
  <br>
  <label for="D=">Do(in)=</label>
  <input type="number" id="D">
  <br>
  <label for="SMYS">SMYS(psi)=</label>
  <input type="number" id="SMYS">
  <br>
  <label for="DF">DF=</label>
  <input type="number" id="DF">
  <br>
  <label for="T">T=</label>
  <input type="number" id="T">
  <br>
  <label for="E">E &#8521;=</label>
  <input type="number" id="E">
  <br>
  <button type="submit" id="calculate">calculate</button> 
  <br>
  <label for="total">Wall Thickness(in)=</label>
  <input type="number" id="total" readonly>
  <br>
  <label for="SMT">Standerd Manufacturing Thickness (in)=</label>
    <input class="inline" input type="number" id="SMT"> 
  <br>
  <button type="submit" id="Check">Check</button> 
  <script>
  document.getElementById('calculate').addEventListener('click', function() {
  
  var P = +document.getElementById("P").value;
  
  var D = +document.getElementById("D").value;
  
  var SMYS = +document.getElementById("SMYS").value;
  
  var DF = +document.getElementById("DF").value;
  
  var T = +document.getElementById("T").value;
  
  var E = +document.getElementById("E").value;

  var SMT = +document.getElementById("SMT").value;
  
  var total = (P * D) / (2 * SMYS * DF * T * E);
  
  document.getElementById("total").value = total;
  if (SMT / 48 < 135) {
  console.log("pass");
      } else {
  console.log("enter higher value");
      }
    });
  </script>
  </body>