please help me to solve hash table and explain it [closed]

In the hash table below we use open addressing with linear probing to resolve collisions.
The hash function is h(x)=x(mod11). In the table x denotes the places of deleted elements.

     0     1      2     3    4    5    6    7    8    9    10
     11   34     24     x         x    6         x         x

When inserting number 12 what is distance between its hash value and its final position?

Select one or more:

A- 10

B- 1

C- 4

D- 3

E- 9