What the logic behind b1 ? b1 : b2 in my coding in if-conditions?

1.Here is the assignment.

Declare a function or that works like ||, but without using the || operator.
/**

1. @param {any} ??? – the first operand
2. @param {any} ??? – the second operand
3. @returns {any} the same result as applying the || operator to the given operands, in order

2.Here is what tried(actually people gave me advice on return b1 ? b1 : b2.But i couldn’t understand it ,and haven’t found a proper explanation about it online.

function or(b1, b2) {
  if (b1 == false && b2 == false) return false;
  else return b1 ? b1 : b2;
}

3.Here are the coding tests, and the code above passed all of them. But would anyone tell me the logic of b1 ? b1 : b2. I am a beginner, please help me !

//TEST 1

actual = or("bananas", false);

expected = "bananas";

if (actual === expected) {
  console.log("Yay! Test PASSED.");
} else {
  console.error("Test FAILED. Keep trying!");
  console.log("    actual: ", actual);
  console.log("  expected: ", expected);
}

//TEST 2

actual = or("", "bananas");

expected = "bananas";

if (actual === expected) {
  console.log("Yay! Test PASSED.");
} else {
  console.error("Test FAILED. Keep trying!");
  console.log("    actual: ", actual);
  console.log("  expected: ", expected);
}

//TEST 3

actual = or(true, true);

expected = true;

if (actual === expected) {
  console.log("Yay! Test PASSED.");
} else {
  console.error("Test FAILED. Keep trying!");
  console.log("    actual: ", actual);
  console.log("  expected: ", expected);
}

//TEST 4

actual = or(true, false);

expected = true;

if (actual === expected) {
  console.log("Yay! Test PASSED.");
} else {
  console.error("Test FAILED. Keep trying!");
  console.log("    actual: ", actual);
  console.log("  expected: ", expected);
}