Find mongodb docs based on array of object contains two fields

Example: Mongo db collection:

[
  {
    "user_id": 1,
    "lead_id": 901,
     ...
     ...
  },
  {
    "user_id": 2,
    "lead_id": 902,
     ...
     ...
  },
   {
    "user_id": 2,
    "lead_id": 903,
    ...
    ...
  },
 {
    "user_id": 3,
    "lead_id": 999,
    ...
    ...
  },
]

I have an array of objects:

const reqArr = [
  {
    "user_id": 1,
    "lead_id": 901,
  }, 
   {
    "user_id": 2,
    "lead_id": 999,
   }
]

I want to query the DB based on both user_id and lead_id present in each object in the array reqArr. something like this or with aggregate pipeline

Model.find(reqArr)

My desired output would be something like this:

[{
 "user_id": 1,
 "lead_id": 901,
  ...
  ...
}]

I only know how to query based on the array of one field like Model.find({_id: {"$in": [array of ids ]}}) but not with more than one field in an array of object.
Any idea or workaround to achieve something like the above output or negation of the above output? I only need which objects in reqArr are present in db collection or which are not. Thank you.