skip creating arrays of same data [duplicate]

I am extracting the objects from the array team which have the same year value using the array.filter() function. The only problem it creates twice or n times the arrays depending how many times the same date appears because am looping the array. I want to find a way to bypass already created array with same name and date value.

  const team = [{
    name: 'John',
    date: '2022-01-08T00:00:00.000Z',
    team: 'teamA'
  },
  {
    name: 'James',
    date: '2021-03-10T00:00:00.000Z',
    team: 'teamB'
  },
  {
    name: 'Trevor',
    date: '2022-01-08T00:00:00.000Z',
    team: 'teamC'
  },
  {
    name: 'Mike',
    date: '2021-01-08T00:00:00.000Z',
    team: 'teamC'
  },
  {
    name: 'aggelos',
    date: '2019-01-08T00:00:00.000Z',
    team: 'teamC'
  }
];
for (var i = 0; i < team.length; i++) {
  d1 = new Date(team[i].date)
  let currentDate = d1.getFullYear();

  result(currentDate)
}

function result(currentDate) {
  const extracted = team.filter(el => new Date(el.date).getFullYear() === currentDate)
  console.log(extracted)
}

Output:

{
  date: "2022-01-08T00:00:00.000Z",
  name: "John",
  team: "teamA"
}, {
  date: "2022-01-08T00:00:00.000Z",
  name: "Trevor",
  team: "teamC"
}]
[{
  date: "2021-03-10T00:00:00.000Z",
  name: "James",
  team: "teamB"
}, {
  date: "2021-01-08T00:00:00.000Z",
  name: "Mike",
  team: "teamC"
}]
[{
  date: "2022-01-08T00:00:00.000Z",
  name: "John",
  team: "teamA"
}, {
  date: "2022-01-08T00:00:00.000Z",
  name: "Trevor",
  team: "teamC"
}]
[{
  date: "2021-03-10T00:00:00.000Z",
  name: "James",
  team: "teamB"
}, {
  date: "2021-01-08T00:00:00.000Z",
  name: "Mike",
  team: "teamC"
}]
[{
  date: "2019-01-08T00:00:00.000Z",
  name: "aggelos",
  team: "teamC"
}]